document.write( "Question 1090247: When 1000 is divided by some positive integer x, the remainder is 45. What is the sum of the largest and smallest value of x \n" ); document.write( "

Algebra.Com's Answer #704698 by ikleyn(52835) $\"\"$ $\"About$

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document.write( "1.  The condition is equivalent to the fact that  1000-45 = 955  is divisible by  x.\r\n" );
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document.write( "2.  955 = 5*191,  and both  5  and  191  are prime numbers.\r\n" );
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document.write( "3.  Hence,  EITHER x= 5  OR  x= 191.\r\n" );
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document.write( "4.  Thus  5 + 191 = 196  is the answer.\r\n" );
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