document.write( "Question 1090034: what is the area of ellipse with an aspect ratio of two and total perimeter of 25 inches? \n" ); document.write( "
Algebra.Com's Answer #704693 by MathLover1(20850)\"\" \"About 
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what is the area of ellipse with an aspect ratio of two and total perimeter of \"25\" inches? \r
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\n" ); document.write( "\n" ); document.write( "For an ellipse, the aspect ratio denotes the ratio of the major axis \"a\" to the minor axis \"b\".
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\n" ); document.write( "\"a\" and \"b\" are measured from the center, so they are like \"radius\" measures\r
\n" ); document.write( "\n" ); document.write( "given: \"a%2Fb=2\" => \"a=2b\"\r
\n" ); document.write( "\n" ); document.write( "and perimeter \"P=25\" inches\r
\n" ); document.write( "\n" ); document.write( "an approximation within about 5% of the true value, so long as a is not more than 3 times longer than b (in other words, the ellipse is not too \"squashed\"):\r
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\n" ); document.write( "\n" ); document.write( "\"P=2pi%2Asqrt%28%28a%5E2%2Bb%5E2%29%2F2%29\"\r
\n" ); document.write( "\n" ); document.write( "\"25=2pi%2Asqrt%28%28%282b%29%5E2%2Bb%5E2%29%2F2%29\".............solve for \"b\"\r
\n" ); document.write( "\n" ); document.write( "\"b+=+-%285+sqrt%285%2F2%29%29%2Fpi\"\r
\n" ); document.write( "\n" ); document.write( "\"b+\"\"-2.51773699057992\"\r
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\n" ); document.write( "\n" ); document.write( "\"a=2%2A%28-5sqrt%285%2F2%29%29%2Fpi+=+%28-10sqrt%285%2F2%29%29%2Fpi\"\r
\n" ); document.write( "\n" ); document.write( "\"a\"\"+-5.032921210448\"\r
\n" ); document.write( "\n" ); document.write( "Ellipse area is:\r
\n" ); document.write( "\n" ); document.write( "\"Area+=ab%2Api\"\r
\n" ); document.write( "\n" ); document.write( "\"Area+=%28-10+sqrt%285%2F2%29%29%2Fpi%2A%28-5+sqrt%285%2F2%29%29%2Fpi%29%2Api\"\r
\n" ); document.write( "\n" ); document.write( "\"Area+=%28-10+sqrt%285%2F2%29%29%2Fpi%2A%28-5sqrt%285%2F2%29%29\"\r
\n" ); document.write( "\n" ); document.write( "\"Area+=125%2Fpi\"\r
\n" ); document.write( "\n" ); document.write( "\"Area=39.8\" in^2\r
\n" ); document.write( "\n" ); document.write( "check equation:\r
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\n" ); document.write( "\n" ); document.write( "or
\n" ); document.write( "\"x%5E2%2F%28-5.032921210448%29%5E2+%2B+y%5E2%2F%28-2.51773699057992%29%5E2=1\"\r
\n" ); document.write( "\n" ); document.write( "it will give you:\r
\n" ); document.write( "\n" ); document.write( "area | \"39.808917197\"
\n" ); document.write( "perimeter | \"24.383816643\" which is an approximation within about 5% of the true value\r
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