document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1090241>Question 1090241</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how do you find a pattern in a non linear functions? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #704683 by </B><A HREF=/tutors/aboutme.mpl?userid=dennisrizelleruiz><B>dennisrizelleruiz(5)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=dennisrizelleruiz><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=dennisrizelleruiz><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=704683\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> You may want to only new that a linear was y=x, y=kx where k is constant number like y=1x, y=2x, y=3x, y=10x, and so forth and so on. In addition, y=k when k is constant number like y=1, y=2, y=3, y=10, y=45, and so forth and so on. Therefore, the only linear function were x, kx, and k. \r<BR>\n" );
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document.write( "Rmember the graph goes straight line continuously.\r<BR>\n" );
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document.write( "If it was a sequence and series, then you may want to use the formula y=a+(n-1)d where a is the first term such as y=2n substituting the n by 1 which represents number of term like 1 means 1st term, gives you 2 which is the first term; lastly the d represents the difference like the distance of the number with each other. </SPAN>\n" );
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