document.write( "Question 96843: 2x+9times the sq.root of x=5 \n" ); document.write( "
Algebra.Com's Answer #70464 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! 2x+9sqrt(x) = 5 \n" ); document.write( "9sqrt(x) = 5-2x \n" ); document.write( "Square both sides to get: \n" ); document.write( "81x = 25-20x+4x^2 \n" ); document.write( "4x^2-101x+25=0 \n" ); document.write( "x = [101 +- sqrt(101^2-4*4*25)]/8\r \n" ); document.write( "\n" ); document.write( "x = [101 +- sqrt(9801)]/8\r \n" ); document.write( "\n" ); document.write( "x = [101 +- 99]/8\r \n" ); document.write( "\n" ); document.write( "x = 1/4 or x = 25 \n" ); document.write( "=========== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |