document.write( "Question 96843: 2x+9times the sq.root of x=5 \n" ); document.write( "
Algebra.Com's Answer #70464 by stanbon(75887)\"\" \"About 
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2x+9sqrt(x) = 5
\n" ); document.write( "9sqrt(x) = 5-2x
\n" ); document.write( "Square both sides to get:
\n" ); document.write( "81x = 25-20x+4x^2
\n" ); document.write( "4x^2-101x+25=0
\n" ); document.write( "x = [101 +- sqrt(101^2-4*4*25)]/8\r
\n" ); document.write( "\n" ); document.write( "x = [101 +- sqrt(9801)]/8\r
\n" ); document.write( "\n" ); document.write( "x = [101 +- 99]/8\r
\n" ); document.write( "\n" ); document.write( "x = 1/4 or x = 25
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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