document.write( "Question 1090222: Given the Earth's radius of 4000 miles, and a mass of 200 pounds:
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\n" ); document.write( "The weight on the surface is 200 pounds.
\n" ); document.write( "What is the weight in an elevator to the Earth's center at various depths?
\n" ); document.write( "Depth of 500 miles, 1000 miles, 2000 miles, etc.
\n" ); document.write( "-\Ignore any effects of pressure and temperature.
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Algebra.Com's Answer #704639 by Fombitz(32388)\"\" \"About 
You can put this solution on YOUR website!
The assumption here is that the Earth is a point mass.
\n" ); document.write( "All of the mass of the Earth is concentrated at the point where the radius is equal to zero (or a small
\n" ); document.write( "value compared to the radius of the Earth and the values where the measurements are taken).
\n" ); document.write( "Weight is inversely proportional to the distance from the center of the earth.
\n" ); document.write( "\"W=k%2FD%5E2\"
\n" ); document.write( "\"k=WD%5E2\"
\n" ); document.write( "\"k=200%2A%284000%29%5E2\"
\n" ); document.write( "So,
\n" ); document.write( "\"W=%28200%2A%284000%29%5E2%29%2FD%5E2\"
\n" ); document.write( "\"W%2F200=%284000%2FD%29%5E2\"
\n" ); document.write( "Then for example, when \"D=500\"
\n" ); document.write( "\"W%2F200=%284000%2F500%29%5E2\"
\n" ); document.write( "\"W%2F200=%288%29%5E2\"
\n" ); document.write( "\"W=64%2A200\"
\n" ); document.write( "\"W=12800\"\"lbs\"\r
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\n" ); document.write( "Uniform density solution:
\n" ); document.write( "So the gravitational force is a function of the two masses involved and the distance between them.
\n" ); document.write( "\"F=GMm%2FR%5E2\"
\n" ); document.write( "If you allow the mass of the Earth to change as a function of its radius (R) (assuming uniform density)
\n" ); document.write( "\"M=rho%2A%284%2F3%29pi%2AR%5E3=kR%5E3\"
\n" ); document.write( "Substituting,
\n" ); document.write( "\"W=a%2AR%5E3%2Am%2FR%5E2\"
\n" ); document.write( "\"W=a%2AmR\"
\n" ); document.write( "Where \"a\" is a constant (from all of the constants put together).
\n" ); document.write( "So then your mass doesn't change so it's also a constant.
\n" ); document.write( "\"W=bR\"
\n" ); document.write( "You can then use the value at the earth to calculate the value of b.
\n" ); document.write( "\"200=b%284000%29\"
\n" ); document.write( "\"b=1%2F20\"
\n" ); document.write( "So then,
\n" ); document.write( "\"W=R%2F20\" valid for \"0%3CR%3C4000\"
\n" ); document.write( "Again that's a simple solution using uniform density model. \r
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