document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=96832>Question 96832</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hallo,\r<BR>\n" );
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document.write( "my question is, when we add two or more vectors algebraically in two dimension, how can we find the direction of the resultant vector.\r<BR>\n" );
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document.write( "Thanks, Hamad </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #70462 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=70462\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If you have vectors (2,3) and (-1,6)<BR>\n" );
document.write( "Add the corresponding x and y values to get:<BR>\n" );
document.write( "(1,9)<BR>\n" );
document.write( "Then the angle is tan^-1(9/1) = 83.66 degrees<BR>\n" );
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document.write( "Be careful when you take the tan^-1; you must <BR>\n" );
document.write( "remember tan^-1 has a restricted range.<BR>\n" );
document.write( "Visualize where your resultant is so you get<BR>\n" );
document.write( "the proper angle.<BR>\n" );
document.write( "For example: <BR>\n" );
document.write( "If the resultant is (-3,-5), tan^-1(-5/-3) = 59.036.. degrees.<BR>\n" );
document.write( "But that resultant is in the 3rd quadrant. The angle you <BR>\n" );
document.write( "want is 180+59.036 = 239.036 degrees.<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( " </SPAN>\n" );
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