document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1090150>Question 1090150</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A ship traveled at an average rate of  12  miles per hour going east. It then traveled at an average rate of  18  miles per hour heading south. If the ship traveled a total of  156  miles in  10  hours, how many miles were traveled heading east? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #704550 by </B><A HREF=/tutors/aboutme.mpl?userid=jorel1380><B>jorel1380(3719)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jorel1380><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=jorel1380><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=704550\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let n be the amount of time spent going east. Then, the amount of time spent going south would be 10-n. So:<BR>\n" );
document.write( "(12n)²+18²(10-n)²=156²<BR>\n" );
document.write( "144n²+32400-6480n+324n²=24336<BR>\n" );
document.write( "468n²-6480n+8064=0<BR>\n" );
document.write( "Solve for n<BR>\n" );
document.write( "&#9786;&#9786;&#9786;&#9786; </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );