document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1090120>Question 1090120</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Sorry I don't know which type it is.<BR>\n" );
document.write( "Question:<BR>\n" );
document.write( "It is given that the ratio of two numbers is 3:7. If 6 is subtracted from both numbers, their ratio will become 1:3. What is the ratio of number if 6 is added to both numbers?<BR>\n" );
document.write( "Thank you very much! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #704518 by </B><A HREF=/tutors/aboutme.mpl?userid=htmentor><B>htmentor(1343)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=htmentor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=htmentor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=704518\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x/y = 3/7 -> 7x = 3y -> y = 7/3x<BR>\n" );
document.write( "(x-6)/(y-6) = 1/3<BR>\n" );
document.write( "Substitute the value for y above in the 2nd equation<BR>\n" );
document.write( "(x-6)/((7/3)x-6) = 1/3<BR>\n" );
document.write( "Solve for x:<BR>\n" );
document.write( "3x - 7/3x = 12<BR>\n" );
document.write( "This gives x = 18<BR>\n" );
document.write( "Thus y = 7*18/3 = 42<BR>\n" );
document.write( "So the ratio if 6 is added to both is 24/48 = 1/2<BR>\n" );
document.write( " </SPAN>\n" );
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