document.write( "Question 1090060: Hello, I'd like to know how to solve the following Logarithmic
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\n" ); document.write( "I ended up doing this= 5·5^3x=5^1/2\r
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Algebra.Com's Answer #704473 by Edwin McCravy(20060)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "\"log%28125%2C%281%2F5%29%29\"\"%22%22=%22%22\"\"x\"\r\n" );
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document.write( "ANY logarithmic equation logB(A) = C\r\n" );
document.write( "is equivalent to the exponential equation A = BC.\r\n" );
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document.write( "Therefore your logarithmic equation is equivalent to\r\n" );
document.write( "the exponential equation \r\n" );
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document.write( "\"1%2F5\"\"%22%22=%22%22\"\"125%5Ex\"\r\n" );
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document.write( "Next we write 1/5 as 5-1 and 125 as (53)\r\n" );
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document.write( "\"5%5E%28-1%29\"\"%22%22=%22%22\"\"%285%5E3%29%5Ex\"\r\n" );
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document.write( "We multiply the exponents on the right to remove the\r\n" );
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document.write( "\"5%5E%28-1%29\"\"%22%22=%22%22\"\"5%5E%283x%29\"\r\n" );
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document.write( "Now Since the bases of the exponents on the laft and right are\r\n" );
document.write( "equal, positive, and different from 1, the exponents must also\r\n" );
document.write( "be equal, so we can drop the bases and set the exponents equal:\r\n" );
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document.write( "\"-1\"\"%22%22=%22%22\"\"3x\"\r\n" );
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document.write( "Divide both sides by 3\r\n" );
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document.write( "\"-1%2F3\"\"%22%22=%22%22\"\"x\"\r\n" );
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document.write( "Edwin
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