document.write( "Question 96811: logx(base of x)of 9 = -2 \n" ); document.write( "
Algebra.Com's Answer #70444 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
\"log%28x%2C9%29=-2\"\r
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\n" ); document.write( "\n" ); document.write( "\"9=x%5E-2\" Rewrite the equation using this property: \"log%28b%2Cx%29=y\" ===> \"b%5Ey=x\"\r
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\n" ); document.write( "\n" ); document.write( "\"9=1%2Fx%5E2\" Flip the variable with the negative exponent\r
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\n" ); document.write( "\n" ); document.write( "\"9x%5E2=1\" Multiply both sides by \"x%5E2\"\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2=1%2F9\" Divide both sides by 9\r
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\n" ); document.write( "\n" ); document.write( "\"x=0%2B-sqrt%281%2F9%29\" Take the square root of both sides\r
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\n" ); document.write( "\n" ); document.write( "So our possible answers are:\r
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\n" ); document.write( "\n" ); document.write( "\"x=1%2F3\" or \"x=-1%2F3\" \r
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\n" ); document.write( "\n" ); document.write( "However, since a negative log is undefined, the only solution is \r
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\n" ); document.write( "\n" ); document.write( "\"x=1%2F3\"
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