document.write( "Question 1089945: Of the 81 people who answered \"yes\" to a question, 6 were male. Of the 70 people that answered \"no\" to the question, 6 were male. If one person is selected at random from the group, what is the probability that the person answered \"yes\" or was male? \n" ); document.write( "

Algebra.Com's Answer #704343 by addingup(3677) $\"\"$ $\"About$

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Total answers: 81Y+70N = 151, thus P(Y) = 81/151
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\n" ); document.write( "Total male answers: 6+6 = 12, thus P(M) = 12/151
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\n" ); document.write( "Of 151 people only 6 males answered \"yes\", thus P(Y and M) = 6/151
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\n" ); document.write( "Now let's put it all together:
\n" ); document.write( "P(Y or M) = P(Y)+P(M)- P(Y and M)
\n" ); document.write( "P(Y or M) = 81/151+12/151+6/151 = 99/151 = 0.6556 \n" ); document.write( "

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