document.write( "Question 1089948: How do I factor 2x^3+10x^2+6x-18=0 . I know the answer is 2(x-1)(x+3)^2. How do I get there ? I know it is not a perfect square so I cannot factor by grouping. I have tried the steps in a difference of cubes and end up having to square root 18 which gives me a decimal so that doesn't work either. Help \n" ); document.write( "

Algebra.Com's Answer #704338 by josgarithmetic(39617) $\"\"$ $\"About$

You can put this solution on YOUR website!
$\"2%28x%5E3%2B5x%5E2%2B3x-9%29=0\"$
\n" ); document.write( "and then by Rational Roots Theorem some possible roots to try testing are -3, -1, 1, 3.\r
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document.write( "1   |   1   5   3   -9\r\n" );
document.write( "    |       1   6   9\r\n" );
document.write( "    |_____________________\r\n" );
document.write( "       1    6   9    0\r\n" );
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document.write( "     Meaning the next factor to break further if possible is  .\r\n" );
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\n" ); document.write( "\n" ); document.write( " $\"2%28x-1%29%28x%5E2%2B6x%2B9%29=0\"$ , and the quadratic factor is easily factored further:\r
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\n" ); document.write( "\n" ); document.write( " $\"2%28x-1%29%28x%2B3%29%28x%2B3%29=0\"$ \n" ); document.write( "

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