document.write( "Question 1089943: if the perimeter of a rhombus is 40 cm and one of its diagonals is 12cm, find the other diagonal \n" ); document.write( "
Algebra.Com's Answer #704332 by MathLover1(20850)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "A rhombus is a flat shape with \"4\" equal straight sides.
\n" ); document.write( "Opposite sides are parallel, and opposite angles are equal (it is a parallelogram).
\n" ); document.write( "And the diagonals \"\"p\"\" and \"\"q\"\" of a rhombus bisect each other at \"right\" angles.\r
\n" ); document.write( "\n" ); document.write( "Perimeter: \"P+=+4s\"\r
\n" ); document.write( "\n" ); document.write( "if the perimeter of a rhombus is \"40cm\" and one of its diagonals is \"12cm\", we have:\r
\n" ); document.write( "\n" ); document.write( "\"4s=40cm\"
\n" ); document.write( "\"s=40cm%2F4\"
\n" ); document.write( "\"s=10cm\"\r
\n" ); document.write( "\n" ); document.write( "so, we have:
\n" ); document.write( "side \"s=10cm\"
\n" ); document.write( "diagonal \"p=12cm\"\r
\n" ); document.write( "\n" ); document.write( "since \"s\", \"p%2F2\", and \"q%2F2\" form right triangle, we can find \"q%2F2\" using Pythagorean theorem:\r
\n" ); document.write( "\n" ); document.write( "\"s%5E2=%28q%2F2%29%5E2%2B%28p%2F2%29%5E2\"\r
\n" ); document.write( "\n" ); document.write( "\"%2810cm%29%5E2-%2812cm%2F2%29%5E2=%28q%2F2%29%5E2\"\r
\n" ); document.write( "\n" ); document.write( "\"%28q%2F2%29%5E2=100cm%5E2-%286cm%29%5E2\"\r
\n" ); document.write( "\n" ); document.write( "\"%28q%2F2%29%5E2=100cm%5E2-36cm%5E2\"\r
\n" ); document.write( "\n" ); document.write( "\"%28q%2F2%29%5E2=64cm%5E2\"\r
\n" ); document.write( "\n" ); document.write( "\"q%2F2=sqrt%2864cm%5E2%29\"\r
\n" ); document.write( "\n" ); document.write( "\"q%2F2=8cm\"\r
\n" ); document.write( "\n" ); document.write( "\"q=8cm%2A2\"\r
\n" ); document.write( "\n" ); document.write( "\"q=16cm\"\r
\n" ); document.write( "\n" ); document.write( "so, the length of the other diagonal is \"16cm\"\r
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