document.write( "Question 1089888: How many ounces of an alloy containing 35% aluminum must be melted with an alloy containing 65% aluminum to obtain 30 ounces of an alloy containing 55% aluminum? \n" ); document.write( "
Algebra.Com's Answer #704267 by ankor@dixie-net.com(22740)\"\" \"About 
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How many ounces of an alloy containing 35% aluminum must be melted with an alloy containing 65% aluminum to obtain 30 ounces of an alloy containing 55% aluminum?
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\n" ); document.write( "Let x = amt of 35% alloy
\n" ); document.write( "then
\n" ); document.write( "(30-x) = amt of 65% alloy
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\n" ); document.write( "A mixture equation
\n" ); document.write( ".35x + .65(30-x) = .55(30)
\n" ); document.write( ".35x + 19.5 - .65x = 16.5
\n" ); document.write( ".35x - .65x = 16.5 - 19.5
\n" ); document.write( "-.30x = -3
\n" ); document.write( "x = -3/-.3
\n" ); document.write( "x = +10 oz of the 35% alloy required
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