document.write( "Question 1089810: 5.
\n" ); document.write( "Use the rational zeros theorem to list the potential rational zeros of the polynomial function. Do not attempt to find the zeros.\r
\n" ); document.write( "\n" ); document.write( "f (x) = 2x^11−x^9+ 3x^8 + 28\r
\n" ); document.write( "\n" ); document.write( "Find the potential Rational zeros.\r
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\n" ); document.write( "A.
\n" ); document.write( "−1, 1, −2, 2, −4, 4, −7, 7, −14, 14, −28, 28, −1/2, 1/2, −7/2, 7/2\r
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\n" ); document.write( "B.
\n" ); document.write( "−1, 1, −2, 2, −4, 4, −7, 7, −28, 28, −1/2, 1/2, −1/28, 1/28\r
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\n" ); document.write( "C.
\n" ); document.write( "−1, 1, −2, 2, −4, 4, −7, 7, −28, 28, −1/2, 1/2, −7/2, 7/2, −1/28, 1/28\r
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\n" ); document.write( "D.
\n" ); document.write( "−1, 1, −2, 2, −4, 4, −7, 7, −14, 14, −28, 28, −1/2, 1/2, −1/28, 1/28\r
\n" ); document.write( "\n" ); document.write( "Choose A, B, C, OR D. (SHOW WORK)
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Algebra.Com's Answer #704204 by math_helper(2461)\"\" \"About 
You can put this solution on YOUR website!
All the potential zeros have the form p/q where p is a factor of the constant term and q is a factor of the leading coefficient. Since the constant term is 28, p can take on +/- { 1,2,4,7,14,28}. Since the leading coefficient is 2, q can take on values +/-{1,2}
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\n" ); document.write( "Answer A is the only one that has all p/q that fit these constraints.
\n" ); document.write( "[ It is easy to eliminate the other choices because they each have +/- 1/28 ].
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