document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=96799>Question 96799</A>: <I><SPAN STYLE=\"word-break: break-all;\"> find three consecutive even integers such that four times the sum of the first and third integers is twenty less than six time the middle integer </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #70420 by </B><A HREF=/tutors/aboutme.mpl?userid=edjones><B>edjones(8007)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=edjones><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=edjones><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=70420\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x, x+2, x+4 are the three integers<BR>\n" );
document.write( "4(x+x+4)=4 times the sum of the 1st and 3rd.<BR>\n" );
document.write( "6(x+2)=6 times the middle.<BR>\n" );
document.write( "Don't forget to add 20 to the left side to make it equal to the right!<BR>\n" );
document.write( "4(2x+4)+20=6(x+2)<BR>\n" );
document.write( "8x+16+20=6x+12<BR>\n" );
document.write( "subtract 6x and 36 from both sides.<BR>\n" );
document.write( "2x=-24<BR>\n" );
document.write( "divide 2 into both sides. x=-12 x+2=-10 x+4=-8<BR>\n" );
document.write( "Check:<BR>\n" );
document.write( "4(-12+(-8))=4*-20=-80<BR>\n" );
document.write( "6*-10=-60<BR>\n" );
document.write( "-80 is 20 less than -60<BR>\n" );
document.write( "Ed<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );