document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=96782>Question 96782</A>: <I><SPAN STYLE=\"word-break: break-all;\"> if the length of a rectangle is 3 inches longer than the width and the perimeter of the rectangle is 78. what is the equation involving only the length? also solve the equation finding the length and the width. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #70416 by </B><A HREF=/tutors/aboutme.mpl?userid=ptaylor><B>ptaylor(2198)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ptaylor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ptaylor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=70416\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let l-Length of rectangle<BR>\n" );
document.write( "Length(l)=Width(w)+3  subtract 3 from both sides\r<BR>\n" );
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document.write( "l-3=w+3-3 or\r<BR>\n" );
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document.write( "w=l-3\r<BR>\n" );
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document.write( "Now we know that the perimeter =2l+2w or\r<BR>\n" );
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document.write( "78=2l+2(l-3)  get rid of parens\r<BR>\n" );
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document.write( "78=2l+2l-6  add 6 to both sides\r<BR>\n" );
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document.write( "78+6=2l+2l-6+6  collect like terms\r<BR>\n" );
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document.write( "4l=84  divide both sides by 4\r<BR>\n" );
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document.write( "l=21-----------------------------------length of rectangle\r<BR>\n" );
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document.write( "w=l-3=21-3=18----------------------------width of rectangle\r<BR>\n" );
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document.write( "CK<BR>\n" );
document.write( "2*21+2*18=78\r<BR>\n" );
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document.write( "42+36=78<BR>\n" );
document.write( "78=78<BR>\n" );
document.write( "Length is 3\" longer than width\r<BR>\n" );
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document.write( "21 is 3 more than 18\r<BR>\n" );
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document.write( "Hope this helps----ptaylor </SPAN>\n" );
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