document.write( "Question 1089759: Permutations, combinations, and the multiplication principle for counting.\r
\n" ); document.write( "\n" ); document.write( "12c 4 12/4= 12/4/8=165
\n" ); document.write( "11c 3 =11/3 11/3/8=495
\n" ); document.write( " I am needing a better explanation on how the answer comes up to 165 and how they got 495 please show me all the steps I am missing something \n" ); document.write( "
Algebra.Com's Answer #704124 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
It seems like the two values have been mixed up somehow.\r
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\n" ); document.write( "\n" ); document.write( "Here's what it should be:\r
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\n" ); document.write( "\n" ); document.write( "n C r = (n!)/(r!*(n-r)!)
\n" ); document.write( "12 C 4 = (12!)/(4!*(12-4)!)
\n" ); document.write( "12 C 4 = (12!)/(4!*8!)
\n" ); document.write( "12 C 4 = (12*11*10*9*8!)/(4!*8!)
\n" ); document.write( "12 C 4 = (12*11*10*9)/(4!)
\n" ); document.write( "12 C 4 = (12*11*10*9)/(4*3*2*1)
\n" ); document.write( "12 C 4 = 11880/24
\n" ); document.write( "12 C 4 = 495\r
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\n" ); document.write( "\n" ); document.write( "n C r = (n!)/(r!*(n-r)!)
\n" ); document.write( "11 C 3 = (11!)/(3!*(11-3)!)
\n" ); document.write( "11 C 3 = (11!)/(3!*8!)
\n" ); document.write( "11 C 3 = (11*10*9*8!)/(3!*8!)
\n" ); document.write( "11 C 3 = (11*10*9)/(3!)
\n" ); document.write( "11 C 3 = (11*10*9)/(3*2*1)
\n" ); document.write( "11 C 3 = 990/6
\n" ); document.write( "11 C 3 = 165
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