document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=96762>Question 96762</A>: <I><SPAN STYLE=\"word-break: break-all;\"> In 1975 the popultation of the earth was approximately 4 billion and dobuling every 35 years.  The formula for the population P in Year Y for this doubling rate is P(in billions) = 4x 2(y-1975)/35.  What will the population be in 2025 if tis growth rate continues? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #70407 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=70407\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> P(year) = 4x 2^[(y-1975)/35]: P in billions.<BR>\n" );
document.write( " What will the population be in 2025 if tis growth rate continues?<BR>\n" );
document.write( "---------<BR>\n" );
document.write( "P(2025)= 4*2^[(2025-1975)/35]<BR>\n" );
document.write( "= 4^2^(50/35)<BR>\n" );
document.write( "= 4*2^(10/7)<BR>\n" );
document.write( "= 4*2^(1.42857...)<BR>\n" );
document.write( "=4*2.6918...<BR>\n" );
document.write( "=10.7672... billion<BR>\n" );
document.write( "=================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );