document.write( "Question 1089715: If (x-6)^2 = 0, what is the value of 3x? \n" ); document.write( "
Algebra.Com's Answer #704067 by jim_thompson5910(35256)\"\" \"About 
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\n" ); document.write( "If (x-6)^2 = 0, then x = 6 as shown by the steps below
\n" ); document.write( "(x-6)^2 = 0
\n" ); document.write( "sqrt((x-6)^2) = sqrt(0)
\n" ); document.write( "x-6 = 0
\n" ); document.write( "x-6+6 = 0+6
\n" ); document.write( "x = 6\r
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\n" ); document.write( "\n" ); document.write( "We can confirm this by plugging in x = 6
\n" ); document.write( "(x-6)^2 = 0
\n" ); document.write( "(6-6)^2 = 0
\n" ); document.write( "(0)^2 = 0
\n" ); document.write( "0 = 0\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Because x = 6, we can then say
\n" ); document.write( "3x = 3*6 = 18
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