document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1089680>Question 1089680</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Eight hours after a runner and cyclist leave the house at the same time and head in the same direction, the cyclist is 88 miles ahead of the runner. If the cyclist's speed is 2 mph more than twice the speed of runner, find the speed of the runner and the cyclist. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #704017 by </B><A HREF=/tutors/aboutme.mpl?userid=jorel1380><B>jorel1380(3719)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jorel1380><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=jorel1380><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=704017\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let n be the speed of the runner. Then the cyclist's speed is 2n+2. So:<BR>\n" );
document.write( "8(2n+2)-8n=88<BR>\n" );
document.write( "16n+16-8n=88<BR>\n" );
document.write( "8n=72<BR>\n" );
document.write( "n=9<BR>\n" );
document.write( "2n+2=20<BR>\n" );
document.write( "&#9786;&#9786;&#9786;&#9786; </SPAN>\n" );
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