document.write( "Question 1089625: Island A is 160 miles from island B. A ship captain travels 220 miles from island A and then finds that he is off course and 200 miles from island B. What bearing should he turn to, so he is heading straight towards island B? \n" ); document.write( "
Algebra.Com's Answer #704006 by ankor@dixie-net.com(22740)\"\" \"About 
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Island A is 160 miles from island B. A ship captain travels 220 miles from island A and then finds that he is off course and 200 miles from island B.
\n" ); document.write( " What bearing should he turn to, so he is heading straight towards island B?
\n" ); document.write( ":
\n" ); document.write( "Draw this out as a triangle ABC where A & B are the islands and C it the point that the ship changes it's heading towards B
\n" ); document.write( " Use the law of cosines; c^2 = a^2 + b^2 - 2(ab)Cos(C), where
\n" ); document.write( "a = 200
\n" ); document.write( "b = 220
\n" ); document.write( "c = 160
\n" ); document.write( "Arrange as
\n" ); document.write( "2(ab)Cos(C) = a^2 + b^2 - c^2
\n" ); document.write( "2(200*220)Cos(C) = 200^2 + 220^2 - 160^2
\n" ); document.write( "2(44000)Cos(C) = 40000 + 48400 - 25600
\n" ); document.write( "2(44000)Cos(C) = 62800
\n" ); document.write( "Simplify, divide both sides by 2
\n" ); document.write( "44000*Cos(C) = 31400
\n" ); document.write( "Cos(C) = \"31400%2F44000\"
\n" ); document.write( "Cos(C) = .7136
\n" ); document.write( "ArcCos = 44.47 degree, therefore
\n" ); document.write( "180 - 44.47 = 135.5 degree turn to head towards Island B
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