document.write( "Question 1089558: Use Descartes's Rule of Signs to determine the possible number of positive and negative real zeros for the given function.
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document.write( "F(x)= 2x^3 -5x^2 +x+4
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document.write( "*2 or 0 positive zeros, 2 or 0 negative zeros
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document.write( "*3 or 1 positive zeros, 3 or 1 negative zeros
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document.write( "*2 or 0 positive zeros, 1 or 0 negative zeros
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document.write( "*2 or 0 positive zeros, 1 negative zero \n" );
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Algebra.Com's Answer #703972 by MathLover1(20850)![]() ![]() You can put this solution on YOUR website! The rule states that if the terms of a single-variable polynomial with real coefficients are ordered by descending variable exponent, then the number of positive roots of the polynomial is either equal to the number of sign differences between consecutive nonzero coefficients, or is less than it by an even number.\r \n" ); document.write( "\n" ); document.write( "So, coefficients are \n" ); document.write( "\n" ); document.write( "As can be seen there are \n" ); document.write( "\n" ); document.write( "This means that there are \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "To find number of negative real roots substitute \n" ); document.write( "\n" ); document.write( "Coefficients are \n" ); document.write( "\n" ); document.write( "As can be seen there is \n" ); document.write( "all signs are -, only - (in front of 1) changes to +(in front of 4)\r \n" ); document.write( "\n" ); document.write( "This means that there is \n" ); document.write( "\n" ); document.write( "Answer:\r \n" ); document.write( "\n" ); document.write( "* \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |