document.write( "Question 1089604: If the center of circle x^2 +y^2 -4x-6y-3 =0 is (h,k) and the radius is r, then h+k+r=?
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Algebra.Com's Answer #703954 by MathLover1(20850)\"\" \"About 
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\"x%5E2+%2By%5E2+-4x-6y-3+=0\" is (\"h\",\"k\") and the radius is \"r\", then \"h%2Bk%2Br\"=?\r
\n" ); document.write( "\n" ); document.write( "\"x%5E2+-4x+%2By%5E2-6y-3+=0\"\r
\n" ); document.write( "\n" ); document.write( "\"%28x%5E2+-4x%2B2%5E2%29-2%5E2+%2B%28y%5E2-6y%2B3%5E2%29-3%5E2=3\"\r
\n" ); document.write( "\n" ); document.write( "\"%28x+-2%29%5E2-4+%2B%28y-3%29%5E2-9=3\"\r
\n" ); document.write( "\n" ); document.write( "\"%28x+-2%29%5E2+%2B%28y-3%29%5E2=3%2B4%2B9\"\r
\n" ); document.write( "\n" ); document.write( "\"%28x+-2%29%5E2+%2B%28y-3%29%5E2=16\"\r
\n" ); document.write( "\n" ); document.write( "\"%28x+-2%29%5E2+%2B%28y-3%29%5E2=4%5E2\"\r
\n" ); document.write( "\n" ); document.write( "=> \"h=2\", \"k=3\", \"r=4\"\r
\n" ); document.write( "\n" ); document.write( "then \"h%2Bk%2Br=2%2B3%2B4=9\"\r
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