document.write( "Question 1089570: Two cars start moving simultaneously in the same direction. The first car moves at 64 mph; the speed of the second car is 40 mph. A half-hour later, another car starts moving in the same direction. The third car reaches the first one 1.5 hours after it reached the second car.\r
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Algebra.Com's Answer #703930 by ikleyn(52776) $\"\"$ $\"About$

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\n" ); document.write( "Two cars start moving simultaneously in the same direction. The first car moves at 64 mph; the speed of the second car is 40 mph.
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document.write( "Let x be the speed of the third car in mph, which is under the question.\r\n" );
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document.write( "The third car reaches the second one in  hours.\r\n" );
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document.write( "The third car reaches the first one in  hours.\r\n" );
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document.write( "The condition says that \r\n" );
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document.write( " -  = 1.5   hour.\r\n" );
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document.write( "Simplify and solve for x.\r\n" );
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document.write( "You first step is to multiply both sides of the equation by (x-64)*(x-40).\r\n" );
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document.write( "I solved it mentally and got the answer x= 80 mph.\r\n" );
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\n" ); document.write( "\n" ); document.write( "For many other solved catching up problems/samples see the lesson\r
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\n" ); document.write( "\n" ); document.write( "Also, you have this free of charge online textbook in ALGEBRA-I in this site\r
\n" ); document.write( "\n" ); document.write( " - ALGEBRA-I - YOUR ONLINE TEXTBOOK.\r
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\n" ); document.write( "\n" ); document.write( "The referred lesson is the part of this textbook under the section \"Word problems\", the topic \"Travel and Distance problems\".\r
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