document.write( "Question 1089429: Let E and F be two mutually exclusive events and suppose P(E) = 0.4 and P(F) = 0.2. Compute the probabilities below.
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\n" ); document.write( "\n" ); document.write( "(c) P(Ec)
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Algebra.Com's Answer #703926 by Edwin McCravy(20064)\"\" \"About 
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Let E and F be two mutually exclusive events and suppose P(E) = 0.4 and P(F) = 0.2. Compute the probabilities below.
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document.write( "Draw the Venn diagram.  Since E and F are mutually exclusive, they\r\n" );
document.write( "do not overlap.  The rectangle represents the entire sample space,\r\n" );
document.write( "which has probability 1.  Therefore the region outside the regions E\r\n" );
document.write( "and F must have probability 0.4, so that all three regions will have\r\n" );
document.write( "probability 1, which means that all three probabilities must total 1.\r\n" );
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\n" ); document.write( "(a) P(E intersection F).
That's the probability of where the circle \r\n" );
document.write( "overlap.  Since they do not overlap, the probability is 0. \r\n" );
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\n" ); document.write( "(b) P(E union F).
That's the probability of being in either of the\r\n" );
document.write( "two circles, which is 0.4+0.2 = 0.6   \r\n" );
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\n" ); document.write( "(c) P(Ec).
That's the probability of not being inside the left circle, which is either \r\n" );
document.write( "gotten by 1-0.4 = 0.6 or by adding the two probabilities\r\n" );
document.write( "not including the left circle which is 0.4+0.2 = 0.6  \r\n" );
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\n" ); document.write( "(d) P(Ec intersection Fc).
That's the probability of not being in E and not being in F, which means being \r\n" );
document.write( "outside both circles.  So the probability is 0.4. \r\n" );
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document.write( "Edwin
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