document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=96676>Question 96676</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve the quadratic equations by completing the square.\r<BR>\n" );
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document.write( "x^2-6x-3=0\r<BR>\n" );
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document.write( "This one I do not have any idea.\r<BR>\n" );
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document.write( "Thank you for your help. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #70391 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=70391\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> completing the square means turning the quadratic into a \"perfect square\"\r<BR>\n" );
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document.write( "first, (using addition or subtraction) move the constant term to the other side of the equation\r<BR>\n" );
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document.write( "x^2-6x=3\r<BR>\n" );
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document.write( "next, (using multiplication or division) set the x^2 coefficient equal to 1 ... already done here\r<BR>\n" );
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document.write( "next, square 1/2 of the x term coefficient and add it to both sides ... -6/2=-3 ... (-3)^2=9\r<BR>\n" );
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document.write( "x^2-6x+9=12 ... (x-3)^2=12\r<BR>\n" );
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document.write( "next, take the square root of both sides ... remembering that square roots are + and -\r<BR>\n" );
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document.write( "x-3=sqrt(12) ... x-3=2(sqrt(3)) ... so x=3+2(sqrt(3)) and x=3-2(sqrt(3))\r<BR>\n" );
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document.write( " </SPAN>\n" );
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