document.write( "Question 1089535: How do you find the focus, directrix, and axis for the following equation:\r
\n" ); document.write( "\n" ); document.write( "10x-y^2+2y+9=0
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Algebra.Com's Answer #703882 by MathLover1(20850)\"\" \"About 
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\"10x-y%5E2%2B2y%2B9=0\" write in vertex form\r
\n" ); document.write( "\n" ); document.write( "\"10x=y%5E2-2y-9\"............complete square\r
\n" ); document.write( "\n" ); document.write( "\"10x=%28y%5E2-2y%2Bb%5E2%29-b%5E2-9\"\r
\n" ); document.write( "\n" ); document.write( "\"10x=%28y%5E2-2y%2B1%5E2%29-1%5E2-9\"\r
\n" ); document.write( "\n" ); document.write( "\"10x=%28y-1%29%5E2-10\"\r
\n" ); document.write( "\n" ); document.write( "\"x=%281%2F10%29%28y-1%29%5E2-1\"\r
\n" ); document.write( "\n" ); document.write( "this is sideway parabola
\n" ); document.write( "general form is:\r
\n" ); document.write( "\n" ); document.write( "\"x=a%28y-k%29%5E2%2Bh\" or\r
\n" ); document.write( "\n" ); document.write( "\"+4p%28x-h%29+=+%28y+-k%29%5E2\"\r
\n" ); document.write( "\n" ); document.write( "as you can see, \"h=-1\" and \"k=1\"\r
\n" ); document.write( "\n" ); document.write( "so, vertex is at (\"-1\",\"1\" )\r
\n" ); document.write( "\n" ); document.write( "since \"a=1%2F10\" and \"4p=1%2Fa\" we can find \"p\" which is distance of focus from vertex
\n" ); document.write( "\"4p=10\"
\n" ); document.write( "\"p=5%2F2\"\r
\n" ); document.write( "\n" ); document.write( "focus:
\n" ); document.write( "(\"h%2Bp\",\"k\")
\n" ); document.write( "=(\"-1%2B5%2F2\",\"1\")
\n" ); document.write( "=(\"3%2F2\",\"1\")\r
\n" ); document.write( "\n" ); document.write( "directrix: will \"p=5%2F2\" distance from the \"x\" coordinate of the vertex
\n" ); document.write( "\"x=+-1-5%2F2\"
\n" ); document.write( " \"x=+-7%2F2\"\r
\n" ); document.write( "\n" ); document.write( "Every parabola has an axis of symmetry which is the line that runs down its 'center'. This line divides the graph into two perfect halves.If your equation is in vertex form, then the axis of is:
\n" ); document.write( "The vertex of this parabola is (\"-1\", \"1\"). The axis of symmetry is at y \"y=k\", so for this example, it is at \"y+=+1\".\r
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