document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1089533>Question 1089533</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Can i need  ur  help for this problem....thank you for the help.....&#128522;\r<BR>\n" );
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document.write( "4x+7y=-2<BR>\n" );
document.write( "6x-8y=5\r<BR>\n" );
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document.write( "Using linear equition substitution and illimination<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #703868 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=703868\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 1)4x+7y = -2<BR>\n" );
document.write( "2) 6x-8y = 5<BR>\n" );
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document.write( "solve equation 2 for x<BR>\n" );
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document.write( "6x = 8y+5<BR>\n" );
document.write( "x = (8y+5)/6<BR>\n" );
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document.write( "substitute for x in equation 1<BR>\n" );
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document.write( "4[(8y+5)/6] +7y = -2<BR>\n" );
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document.write( "(32y+20)/6 +7y = -2<BR>\n" );
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document.write( "multiply both sides of = by 6<BR>\n" );
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document.write( "32y+20 +42y = -12<BR>\n" );
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document.write( "74y = -32<BR>\n" );
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document.write( "y = -32/74 = -16/37 approx &#8722;0.4324<BR>\n" );
document.write( "x = [8(-16/37)+5]/6 approx 0.2568<BR>\n" );
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document.write( "check answer<BR>\n" );
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document.write( "1) 4*(0.2568) +7*(-0.4324) = -2 <BR>\n" );
document.write( "-1.9999 approx -2<BR>\n" );
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document.write( "2) 6*(0.2568) -8*(-0.4324) = 5<BR>\n" );
document.write( "5.0002 approx 5<BR>\n" );
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document.write( "our answer checks<BR>\n" );
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