document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1089530>Question 1089530</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A ball is projected directly upward from and initial height of 200 feet with an initial velocity of 120 feet per second. After how many seconds does the ball reach its maximum height? What is this height? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #703866 by </B><A HREF=/tutors/aboutme.mpl?userid=jorel1380><B>jorel1380(3719)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jorel1380><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=jorel1380><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=703866\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The equation for this ball's movement would be h(t)=-16t²+120t+200, where t is time and h(t) is the ball's height at any given t. The ball will reach its maximum height at t=-b/2a, where b is the initial velocity(120), and a is the acceleration (-16a). In this case, -b/2a=-120/-32=3.75 seconds before the ball reaches its maximum height. Then:<BR>\n" );
document.write( "-16(3.75²)+120(3.75)+200=425 ft is the ball's maximum height. <BR>\n" );
document.write( "&#9786;&#9786;&#9786;&#9786; </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );