document.write( "Question 1089494: One number is 10 less than a second number. Twice the second number is 59 more than 5 times the first. Find the two numbers? \n" ); document.write( "
Algebra.Com's Answer #703856 by math_helper(2461)\"\" \"About 
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Let n = the first number
\n" ); document.write( "Let m = the 2nd number\r
\n" ); document.write( "\n" ); document.write( "\"+n+=+m+-+10+\" —> \"+m-n+=+10+\" (1)
\n" ); document.write( "\"+2m+=+59%2B5n+\" —> \"+2m-5n+=+59+\" (2)\r
\n" ); document.write( "\n" ); document.write( "2*(1) —> \"+2m+-+2n+=+20+\"
\n" ); document.write( "subtract (2) \"+2m-5n+=+59+\"
\n" ); document.write( "resulting in: \"++3n+=+-39+\"\r
\n" ); document.write( "\n" ); document.write( "Ans: \"+highlight%28n+=+-13%29\" and \"+highlight%28m+=+-3+%29\"
\n" ); document.write( "——
\n" ); document.write( "Check: -13 is 10 less than -3 (ok)
\n" ); document.write( " 2(-3) = -6
\n" ); document.write( " 59 + 5(-13) = 59+(-65) = -6 (ok)
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