document.write( "Question 1089434: I am having a really hard time trying to figure out how to figure out the median of frequency distribution. I have figured out how to find the mean and mode, but I can't figure out the median to save my life.
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document.write( "I've looked at all the helps and how to's but I just can't figure it out. If it could be explained as simply as possible, I would greatly appreciate it! Thank you so much in advance!\r
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document.write( "Value | Frequency
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document.write( "625 | 14
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document.write( "541 | 7
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document.write( "603 | 8
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document.write( "575 | 16
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document.write( "580 | 5
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document.write( "593 | 5 \n" );
document.write( "
Algebra.Com's Answer #703778 by natolino_2017(77) ![]() You can put this solution on YOUR website! we need to organize the data according to the value column\r \n" ); document.write( "\n" ); document.write( "Value | Frequency| Absolut Frecuency \n" ); document.write( "------------------ \n" ); document.write( "541 | 7 | 7 \n" ); document.write( "575 | 16 | 23 \n" ); document.write( "580 | 5 | 28 \n" ); document.write( "593 | 5 | 33 \n" ); document.write( "603 | 8 | 41 \n" ); document.write( "625 | 14 | 55\r \n" ); document.write( "\n" ); document.write( "Median Position = (total cases +1)/2 =(55+1)/2 = 28.\r \n" ); document.write( "\n" ); document.write( "So Median is 580\r \n" ); document.write( "\n" ); document.write( "**Interpretation: there are 27 cases below or equal to 580 and 27 cases \n" ); document.write( "above or equal to 580**\r \n" ); document.write( "\n" ); document.write( "@natolino_\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |