document.write( "Question 1089420: Given the system of linear equations, -x + y = 5 and 4x + y = 10 I am trying to use substitution to find the solution to this linear equation and algebraically to verify my answer this is how i got thus far
\n" ); document.write( "-x + y = 5
\n" ); document.write( "4x(-x + y) = 5
\n" ); document.write( " -4x + 4y = 5 - 10
\n" ); document.write( " -4x = -5
\n" ); document.write( " 4y = -5
\n" ); document.write( " 4 4
\n" ); document.write( " 0 does not = -1 am I doing this right it does not lllook right to me
\n" ); document.write( "

Algebra.Com's Answer #703751 by MathLover1(20850)\"\" \"About 
You can put this solution on YOUR website!
\"-x+%2B+y+=+5\".....eq.1
\n" ); document.write( "\"4x+%2B+y+=+10\".........eq2
\n" ); document.write( "------------------------------------
\n" ); document.write( "if you want to use substitution, start with eq.1 and solve it for \"x\" or \"y\"\r
\n" ); document.write( "\n" ); document.write( "\"-x+%2B+y+=+5\".....eq.1 I will solve it or \"y\"\r
\n" ); document.write( "\n" ); document.write( "\"-x+%2Bx%2B+y+=+x%2B5\"\r
\n" ); document.write( "\n" ); document.write( "\"y+=+x%2B5\".....substitute it in eq2\r
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\n" ); document.write( "\n" ); document.write( "\"4x+%2B+%28x%2B5%29+=+10\".........eq2...solve \"x\"\r
\n" ); document.write( "\n" ); document.write( "\"4x+%2B+x%2B5+=+10\"\r
\n" ); document.write( "\n" ); document.write( "\"5x+=+10-5\"\r
\n" ); document.write( "\n" ); document.write( "\"5x+=+5\"\r
\n" ); document.write( "\n" ); document.write( "\"highlight%28x+=+1%29\"\r
\n" ); document.write( "\n" ); document.write( "now, go to \"y+=+x%2B5\".....substitute \"x+=+1\" and solve \"y\"\r
\n" ); document.write( "\n" ); document.write( " \"y+=+1%2B5\"
\n" ); document.write( " \"highlight%28y+=+6%29\"\r
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