document.write( "Question 1089379: A jet flow at an average speed of 280 mph from Point X to Point Y. Because of head winds, the jet averaged only 260 miles on the return trip, the return trip took 10 minutes longer. How many hours was the flight from Point Y to Point X?\r
\n" ); document.write( "\n" ); document.write( "Please help. Thanks. \n" ); document.write( "

Algebra.Com's Answer #703741 by ikleyn(52781) $\"\"$ $\"About$

You can put this solution on YOUR website!
.
\n" ); document.write( "

\r\n" );
document.write( "We are given:\r\n" );
document.write( "\r\n" );
document.write( "    Average speed of 280 mph from X to Y.\r\n" );
document.write( "    Average speed of 260 mph from Y to X.\r\n" );
document.write( "    Time for the flight (Y --> X) is 12 minutes longer than that for (x --> Y).\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "Let t be the time for the flight (Y --> X)  (which is under the question).\r\n" );
document.write( "\r\n" );
document.write( "Then  280*(t-1/6) = 260*t.   (1)\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "This equation says that the distance was the same for both flights.\r\n" );
document.write( "\r\n" );
document.write( "Notice that  =  of an hour = 10 minutes.\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "From (1) you have \r\n" );
document.write( "\r\n" );
document.write( "280*t - 280/6 = 260*t  ====>  280*t - 260t = -280/6  ====>  20*t = 280/6  ====>  t =  =  =  =  hours.\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "Answer.  The flight from Y to X was   hours.\r\n" );
document.write( "

\r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "

\n" );