document.write( "Question 1089288: How many liters of a 20% solution of acid should be added to 10 liters of a 30% solution of acid to obtain a 25% solution? \n" ); document.write( "
Algebra.Com's Answer #703638 by Edwin McCravy(20056)\"\" \"About 
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document.write( "How many liters of a 20% solution of acid \r\n" );
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document.write( "That's 20% of x liters of solution which will include 0.20x liters of pure acid. \r\n" );
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document.write( "should be added to 10 liters of a 30% solution of acid \r\n" );
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document.write( "That's 30% of 10 liters of solution which will include 0.30(10) or 3 liters \r\n" );
document.write( "of pure acid. \r\n" );
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document.write( "to obtain a 25% solution.\r\n" );
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document.write( "That's 25% of x+10 liters of solution which will include 0.25(x+10) liters of pure acid. \r\n" );
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document.write( "Therefore the equation is:\r\n" );
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document.write( "0.20x + 0.30(10) = 0.25(x+10)\r\n" );
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document.write( "The first step is to multiply every term by 100 to\r\n" );
document.write( "remove the decimals:\r\n" );
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document.write( "20x + 30(10) = 25(x+10)\r\n" );
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document.write( "You can finish solving that.\r\n" );
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document.write( "Edwin
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