document.write( "Question 1089262: factor by grouping \n" );
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Algebra.Com's Answer #703599 by Theo(13342)![]() ![]() You can put this solution on YOUR website! i think this would be factored as follows.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "start with x^3 + y^3 - x^2y - xy^2\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "rearrange by descending order of degree of x.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "you get:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x^3 - x^2y - xy^2 + y^3\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "group as shown below:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(x^3 - x^2y) - (xy^2 - y^3)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "on the left group, factor out x^2.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "on the right group, factor out y^2.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "you will get:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x^2 * (x - y) - y^2 * (x - y)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "factor out the common term of (x - y) and you get:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(x^2 - y^2) * (x - y)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(x^2 - y^2) is equal to (x - y) * (x + y)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "your final factored expression becomes:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(x - y) * (x + y) * (x - y)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "this expression should be equivalent to x^3 + y^3 - x^2y - xy^2\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "to see if it is, pick a random value for x and y and see if both expressions give you the same result.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "i'll pick x = 2 and y = 3.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x^3 + y^3 - x^2y - xy^2 is equal to 5\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(x-y) * (x+y) * (x-y) is equal to 5 as well.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "it looks like these expressions are equivalent.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "this is reasonable proof that the factorization was correct.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "you can try it with other random values of x and y and you should see that the expressions are equivalent.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "i redid the experiment with x = 7 and y = 4\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "i got 99 using each expression.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "that solidifies the impression that the factorization was done correctly.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |