document.write( "Question 1089205: The number of ways in which 10 persons can go in two boats, so that there may be 5 on each boat,supposing that two particular persons will not go in the same boat is? \n" ); document.write( "
Algebra.Com's Answer #703597 by ikleyn(52914)\"\" \"About 
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document.write( "= \"2%2AC%5B8%5D%5E4\" = \"2%2A%288%2A7%2A6%2A5%29%2F%281%2A2%2A3%2A4%29\" = 2*70 = 140.\r\n" );
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document.write( "You place these 2 enemies in different boats by 2 ways,\r\n" );
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document.write( "and then you select 4 of 8 to place in one boat; then the remaining 4 are automatically assigned for the other boat.\r\n" );
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\n" ); document.write( "\n" ); document.write( "On combinations, see the lessons\r
\n" ); document.write( "\n" ); document.write( "    - Introduction to Combinations\r
\n" ); document.write( "\n" ); document.write( "    - PROOF of the formula on the number of Combinations\r
\n" ); document.write( "\n" ); document.write( "    - Problems on Combinations\r
\n" ); document.write( "\n" ); document.write( "    - OVERVIEW of lessons on Permutations and Combinations\r
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\n" ); document.write( "\n" ); document.write( "Also,  you have this free of charge online textbook in ALGEBRA-II in this site\r
\n" ); document.write( "\n" ); document.write( "    - ALGEBRA-II - YOUR ONLINE TEXTBOOK.\r
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\n" ); document.write( "\n" ); document.write( "The referred lessons are the part of this online textbook under the topic  \"Combinatorics: Combinations and permutations\". \r
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