document.write( "Question 1089257: Factor by grouping, \"x%5E2%2B6x%2B9-a%5E2\" \n" ); document.write( "
Algebra.Com's Answer #703596 by ikleyn(52833)\"\" \"About 
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document.write( "\"x%5E2%2B6x%2B9-a%5E2\" = \"%28x%2B3%29%5E2\" - \"a%5E2\" = (x+3+a)*(x+3-a).\r\n" );
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