document.write( "Question 1089224: what are x and y in the following two peoblems?\r
\n" ); document.write( "\n" ); document.write( "6xt40y=554 and 8x+20y=472
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Algebra.Com's Answer #703557 by rothauserc(4718)\"\" \"About 
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1) 6x +40y = 554
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\n" ); document.write( "2) 8x+ 20y = 472
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\n" ); document.write( "multiply equation 2 by 2
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\n" ); document.write( "3) 16x +40y = 944
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\n" ); document.write( "subtract equation 1) from equation 3)
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\n" ); document.write( "4) 10x = 390
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\n" ); document.write( "x = 39
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\n" ); document.write( "substitute for x in equation 1)
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\n" ); document.write( "6(39) +40y = 554
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\n" ); document.write( "234 +40y = 554
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\n" ); document.write( "40y = 320
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\n" ); document.write( "y = 8
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\n" ); document.write( "x = 39 and y = 8
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\n" ); document.write( "check the solution by substituting in equation 2 for x and y
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\n" ); document.write( "8(39) + 20(8) = 472
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\n" ); document.write( "312 + 160 = 472
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\n" ); document.write( "472 = 472
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