document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1089221>Question 1089221</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Given the equation, find the ordered pairs using the partially filled in table.\r<BR>\n" );
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document.write( "y=3x+2\r<BR>\n" );
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document.write( "x | y<BR>\n" );
document.write( "0 | ?<BR>\n" );
document.write( "2 | ?<BR>\n" );
document.write( "? | 0<BR>\n" );
document.write( "? | 5 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #703555 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=703555\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <font color=\"black\" face=\"times\" size=\"3\"><BR>\n" );
document.write( "Row 1: \r<BR>\n" );
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document.write( "If x = 0, then \r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y+=+3x%2B2 ALIGN=MIDDLE  ALT=\"y+=+3x%2B2\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y+=+3%280%29%2B2 ALIGN=MIDDLE  ALT=\"y+=+3%280%29%2B2\"   DISABLED_style= \"max-width:90%; height:auto;\" > Replace x with 0\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y+=+0%2B2 ALIGN=MIDDLE  ALT=\"y+=+0%2B2\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y+=+2 ALIGN=MIDDLE  ALT=\"y+=+2\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "So the value x = 0 pairs up with y = 2.\r<BR>\n" );
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document.write( "The fact that x is 0 here indicates we have an y intercept. This is where the graph crosses the y axis.\r<BR>\n" );
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document.write( "Row 2: \r<BR>\n" );
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document.write( "If x = 2, then\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y+=+3x%2B2 ALIGN=MIDDLE  ALT=\"y+=+3x%2B2\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y+=+3%282%29%2B2 ALIGN=MIDDLE  ALT=\"y+=+3%282%29%2B2\"   DISABLED_style= \"max-width:90%; height:auto;\" > Replace x with 2\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y+=+6%2B2 ALIGN=MIDDLE  ALT=\"y+=+6%2B2\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y+=+8 ALIGN=MIDDLE  ALT=\"y+=+8\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "So the value x = 2 pairs up with y = 8.\r<BR>\n" );
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document.write( "Row 3:\r<BR>\n" );
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document.write( "If y = 0, then\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y+=+3x%2B2 ALIGN=MIDDLE  ALT=\"y+=+3x%2B2\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=0+=+3x%2B2 ALIGN=MIDDLE  ALT=\"0+=+3x%2B2\"   DISABLED_style= \"max-width:90%; height:auto;\" > Replace y with 0\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=0-2+=+3x%2B2-2 ALIGN=MIDDLE  ALT=\"0-2+=+3x%2B2-2\"   DISABLED_style= \"max-width:90%; height:auto;\" > Subtract 2 from both sides\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=-2+=+3x ALIGN=MIDDLE  ALT=\"-2+=+3x\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=3x+=+-2 ALIGN=MIDDLE  ALT=\"3x+=+-2\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=3x%2F3+=+-2%2F3 ALIGN=MIDDLE  ALT=\"3x%2F3+=+-2%2F3\"   DISABLED_style= \"max-width:90%; height:auto;\" > Divide both sides by 3\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x+=+-2%2F3 ALIGN=MIDDLE  ALT=\"x+=+-2%2F3\"   DISABLED_style= \"max-width:90%; height:auto;\" > \r<BR>\n" );
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document.write( "So the value x = -2/3 pairs up with y = 0.\r<BR>\n" );
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document.write( "The fact that y is 0 here indicates we have an x intercept. This is where the graph crosses the x axis.\r<BR>\n" );
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document.write( "Row 4:\r<BR>\n" );
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document.write( "If y = 5, then\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y+=+3x%2B2 ALIGN=MIDDLE  ALT=\"y+=+3x%2B2\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=5+=+3x%2B2 ALIGN=MIDDLE  ALT=\"5+=+3x%2B2\"   DISABLED_style= \"max-width:90%; height:auto;\" > Replace y with 5\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=5-2+=+3x%2B2-2 ALIGN=MIDDLE  ALT=\"5-2+=+3x%2B2-2\"   DISABLED_style= \"max-width:90%; height:auto;\" > Subtract 2 from both sides\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=3+=+3x ALIGN=MIDDLE  ALT=\"3+=+3x\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=3x+=+3 ALIGN=MIDDLE  ALT=\"3x+=+3\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=3x%2F3+=+3%2F3 ALIGN=MIDDLE  ALT=\"3x%2F3+=+3%2F3\"   DISABLED_style= \"max-width:90%; height:auto;\" > Divide both sides by 3\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x+=+1 ALIGN=MIDDLE  ALT=\"x+=+1\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "--------------------------------------------------\r<BR>\n" );
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document.write( "Here's a look at the full completed table (updated entries in <font color=red>red</font>)\r<BR>\n" );
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document.write( "<TABLE  border=1>\n" );
document.write( "<tr><th>x</th><th>y</th></tr><tr><TD   DISABLED_style= \"width:150px\">0</TD><TD   DISABLED_style= \"width:150px\"><font color=red>2</font></TD></tr><tr><TD >2</TD><TD ><font color=red>8</font></TD></tr><tr><TD ><font color=red>-2/3</font> (see <font color=blue>note</font> below)</TD><TD >0</TD></tr><tr><TD ><font color=red>1</font></TD><TD >5</TD></tr>\n" );
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document.write( "<font color=blue>note</font>: The value x = -2/3 is approximately equal to x = -0.667 rounded to 3 decimal places\r<BR>\n" );
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document.write( "If we plot all of the points and draw a single straight line through them, then we end up with what is shown below.\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" src = \"https://image.prntscr.com/image/ozDcQy4WTCaVQOsCLcHCNw.png\">\r<BR>\n" );
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document.write( "The four points are\r<BR>\n" );
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document.write( "A = (0, 2)<BR>\n" );
document.write( "B = (2, 8)<BR>\n" );
document.write( "C = (-2/3, 0)<BR>\n" );
document.write( "D = (1, 5)\r<BR>\n" );
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document.write( "where A,B,C,D corresponds to the (x,y) pairings found in row1,row2,row3,row4 in that order. \r<BR>\n" );
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