document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1089149>Question 1089149</A>: <I><SPAN STYLE=\"word-break: break-all;\"> hello , can anyone please help me on these question of normaly distribution question ? i dont understand the question\r<BR>\n" );
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document.write( "the thickness of the gear blanks produced by an automatic lathe is known to be normally distributed, with a mean of 0.05in. and a standard deviation of 0.05in. <BR>\n" );
document.write( "if 10% of the blank are rejected for being too thin, find the value of the lower specification.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #703529 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=703529\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the thickness of the gear blanks produced by an automatic lathe is known to be normally distributed, with a mean of 0.05in. and a standard deviation of 0.05in. <BR>\n" );
document.write( "If 10% of the blanks are rejected for being too thin, find the value of the lower specification.<BR>\n" );
document.write( "Draw a normal curve; put the mean 0.05\" in the middle<BR>\n" );
document.write( "Mark a left-tail with 10% of the area under the curve.<BR>\n" );
document.write( "You want the value that determines that 10% area.<BR>\n" );
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document.write( "Corresponding to that figure you have a normal curve for z-values.<BR>\n" );
document.write( "Find the z-value that determines a left-tail of 10%.<BR>\n" );
document.write( "invnorm(0.10) = -1.2816<BR>\n" );
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document.write( "Find the corresponding thickness value::<BR>\n" );
document.write( "x = z*s+u<BR>\n" );
document.write( "x = -1.2816*0.05+0.05<BR>\n" );
document.write( "Note:: That would be a negative value.<BR>\n" );
document.write( "You probably posted the wrong standard deviatioin value.<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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