document.write( "Question 1089165: convert the equation to standard form by completing the square on x or y. then find the vertex, focus, and directrix of the parabola. finally, graph the parabola\r
\n" ); document.write( "\n" ); document.write( "x^2+14x-12y+13=0
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Algebra.Com's Answer #703518 by josgarithmetic(39618)\"\" \"About 
You can put this solution on YOUR website!
\"-12y=-x%5E2-14x-13\"
\n" ); document.write( "\"12y=x%5E2%2B14x%2B13\"
\n" ); document.write( "\"12y-13=x%5E2%2B14x\"
\n" ); document.write( "\"12y-13%2B49=x%5E2%2B14x%2B49\"
\n" ); document.write( "\"12y%2B36=%28x%2B7%29%5E2\"
\n" ); document.write( "\"highlight%2812%28y%2B3%29=%28x%2B7%29%5E2%29\"------This form of equation allows to easily find vertex, and distance from either focus or directrix.\r
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\n" ); document.write( "\n" ); document.write( "Parabola has vertex as a minimum point.
\n" ); document.write( "Vertex (-7,-3)
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\n" ); document.write( "\"4p=12\"
\n" ); document.write( "\"p=3\"
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\n" ); document.write( "Focus (-7,0)
\n" ); document.write( "Directrix y=-6, \"y=-6\"\r
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\n" ); document.write( "\n" ); document.write( "\"graph%28300%2C300%2C-16%2C4%2C-10%2C10%2C%281%2F12%29x%5E2%2B%287%2F6%29x%2B13%2F12%29\"
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