document.write( "Question 1089137: Meena’s fathers age is 3 years more than 3 times the age of meena.3 years hence meena’s father will be 10 years more than twice the age of meena .Determine the present ages. \n" ); document.write( "
Algebra.Com's Answer #703486 by josgarithmetic(39628)\"\" \"About 
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\"system%28y=3x%2B3%2Cy%2B3=10%2B2%28x%2B3%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "-\r
\n" ); document.write( "\n" ); document.write( "\"y%2B3=2x%2B6%2B10\"
\n" ); document.write( "\"y=2x%2B16-3\"
\n" ); document.write( "\"y=2x%2B13\"\r
\n" ); document.write( "\n" ); document.write( "-\r
\n" ); document.write( "\n" ); document.write( "\"3x%2B3=2x%2B13\"
\n" ); document.write( "\"x%2B3=13\"
\n" ); document.write( "\"highlight%28x=10%29\"-------Meena's age
\n" ); document.write( "-
\n" ); document.write( "\"highlight%28y=33%29\"------Father's age
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