document.write( "Question 1089124: What is the interval where f(x)=lnx/x (x>0) decreases? \n" ); document.write( "
Algebra.Com's Answer #703455 by Theo(13342)\"\" \"About 
You can put this solution on YOUR website!
the derivative of ln(x) / x is equal to (ln(x) - 1) / x^2\r
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\n" ); document.write( "\n" ); document.write( "set this equal to 0 and you'll find a max/min point on the equation of y = ln(x) / x.\r
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\n" ); document.write( "\n" ); document.write( "start with (ln(x) - 1) / x^2 = 0\r
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\n" ); document.write( "\n" ); document.write( "multiply both sides of the equation by x^2 to get ln(x) - 1 = 0\r
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\n" ); document.write( "\n" ); document.write( "add 1 to both sides of the equation to get ln(x) = 1\r
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\n" ); document.write( "\n" ); document.write( "this is true if and only if e^1 = x\r
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\n" ); document.write( "\n" ); document.write( "solve for x to get x = e which is equal to 2.718281828\r
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\n" ); document.write( "\n" ); document.write( "that's a max/min point on the graph.\r
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\n" ); document.write( "\n" ); document.write( "looking at the graph, you see that it's a max point.\r
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\n" ); document.write( "\n" ); document.write( "this means the value of ln(x) / x will be increasing to the left of this max point and decreasing to the right of this max point.\r
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\n" ); document.write( "\n" ); document.write( "the interval where ln(x)/x is decreasing is therefore from x = 2.718281828..... to positive infinity.\r
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\n" ); document.write( "\n" ); document.write( "in interval notation, i believe this will be [2.718281828..., positive infinity)\r
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\n" ); document.write( "\n" ); document.write( "the following graph shows this to be true.\r
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\n" ); document.write( "\n" ); document.write( "the graph rounds the solution to 3 decimal places.\r
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\n" ); document.write( "\n" ); document.write( "as x gets larger, the function ln(x) / x will approach 0 but will never reach 0.\r
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\n" ); document.write( "\n" ); document.write( "note that i didn't figure out what the derivative was.\r
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\n" ); document.write( "\n" ); document.write( "i probably could if i remembered how to do it.\r
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\n" ); document.write( "\n" ); document.write( "since i didn't, i cheated and used an online derivative calculator.\r
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\n" ); document.write( "\n" ); document.write( "it works very well and can be quite useful for you to see if you calculated the derivative correctly.\r
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\n" ); document.write( "\n" ); document.write( "that calculator can be found at http://www.derivative-calculator.net/\r
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