document.write( "Question 1089094: The length of a rectangular piece of cardboard is 15 inches longer than its width. If a 5 inch square is cut from each corner of the cardboard, and the remaining piece is folded up to form a box, the volume of the box is 2,250 cubic inches. Find the sum of the length and the width, in inches, of the original cardboard. \n" ); document.write( "
Algebra.Com's Answer #703419 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! width is x \n" ); document.write( "length is x+15 \n" ); document.write( "after cutting the 5 inch square, which involved both length and width twice \n" ); document.write( "x-10 and x+5 are the dimensions \n" ); document.write( "5 is the height \n" ); document.write( "the volume is (x^2-5x-50)*5=2250 \n" ); document.write( "divide by 5 both sides \n" ); document.write( "x^2-5x-50=450 \n" ); document.write( "x^2-5x-500=0 \n" ); document.write( "(x-25)(x+20)=0 \n" ); document.write( "x=25 inches, only positive root, original width. \n" ); document.write( "x+15=40 inches, original length. \n" ); document.write( "--------------------- \n" ); document.write( "Check. \n" ); document.write( "Box is 15 inches wide by 30 inches long by 5 inches high, and that is a volume of 2250 in^3. \n" ); document.write( " |