document.write( "Question 1089003: The sum of three numbers is 11. The sum of twice the first number,
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document.write( "4 times the second number, and 5 times the third number is 30. The
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document.write( "difference between 6 times the first number and the second number
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document.write( "is 47. Find the three numbers. \n" );
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Algebra.Com's Answer #703334 by Edwin McCravy(20055)![]() ![]() You can put this solution on YOUR website! \r\n" ); document.write( "The sum of three numbers is 11. \r\n" ); document.write( "\r\n" ); document.write( "X + Y + Z = 11\r\n" ); document.write( "\r\n" ); document.write( "The sum of twice the first number, 4 times the second number, \r\n" ); document.write( "and 5 times the third number is 30. \r\n" ); document.write( "\r\n" ); document.write( "2X + 4Y + 5Z = 30\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "The difference between 6 times the first number and the second number \r\n" ); document.write( "is 47. \r\n" ); document.write( "\r\n" ); document.write( "6X - Y = 47\r\n" ); document.write( "\r\n" ); document.write( "So the system is \r\n" ); document.write( "\r\n" ); document.write( "(eq. 1) X + Y + Z = 11\r\n" ); document.write( "(eq. 2) 2X + 4Y + 5Z = 30\r\n" ); document.write( "(eq. 3) 6X - Y = 47\r\n" ); document.write( "\r\n" ); document.write( "Since Z is already eliminated from (eq. 3), we\r\n" ); document.write( "eliminate Z from the other two equations by\r\n" ); document.write( "multiplying (eq. 1) by -5 and adding to (eq. 2)\r\n" ); document.write( "\r\n" ); document.write( " -5X - 5Y - 5Z = -55\r\n" ); document.write( "(eq. 2) 2X + 4Y + 3Z = 30\r\n" ); document.write( "----------------------------\r\n" ); document.write( "(eq. 4) -3X - Y = -25\r\n" ); document.write( "\r\n" ); document.write( "Now multiply (eq. 3) by -1 and add (eq. 4)\r\n" ); document.write( "\r\n" ); document.write( "(eq. 3) 6X - Y = 47\r\n" ); document.write( "\r\n" ); document.write( " -6X + Y = -47\r\n" ); document.write( "(eq. 4) -3X - Y = -25\r\n" ); document.write( "----------------------------\r\n" ); document.write( "(eq. 5) -9X = -72\r\n" ); document.write( " X = 8\r\n" ); document.write( "\r\n" ); document.write( "Substitute 8 for X in (eq. 4)\r\n" ); document.write( "\r\n" ); document.write( "(eq. 4) -3X - Y = -25\r\n" ); document.write( " -3(8) - Y = -25\r\n" ); document.write( " -24 - Y = -25\r\n" ); document.write( " -Y = -1\r\n" ); document.write( " Y = 1 \r\n" ); document.write( "\r\n" ); document.write( "Substitute 8 for X and 1 for Y in (eq. 1)\r\n" ); document.write( "\r\n" ); document.write( "(eq. 1) X + Y + Z = 11\r\n" ); document.write( " 8 + 1 + Z = 11\r\n" ); document.write( " 9 + Z = 11\r\n" ); document.write( " Z = 2\r\n" ); document.write( "\r\n" ); document.write( "So the solution is (X,Y,Z) = (8,1,2)\r\n" ); document.write( "\r\n" ); document.write( "Edwin\n" ); document.write( " |