document.write( "Question 1089003: The sum of three numbers is 11. The sum of twice the first number,
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document.write( "4 times the second number, and 5 times the third number is 30. The
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document.write( "difference between 6 times the first number and the second number
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document.write( "is 47. Find the three numbers. \n" );
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Algebra.Com's Answer #703329 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! x+y+z=11 \n" ); document.write( "2x+4y+5z=30 \n" ); document.write( "6x-y=47 \n" ); document.write( "therefore, y=6x-47 \n" ); document.write( "substitute into the equations \n" ); document.write( "x+6x-47+z=11 or 7x-47+z=11 \n" ); document.write( "2x+4(6x-47)+5z=30 or 26x-188+5z=30 \n" ); document.write( "7x+z=58, z=-7x+58 \n" ); document.write( "substitute that into the equation 26x+5z=218 so that 26x-35x+290=218 \n" ); document.write( "-9x=-72 \n" ); document.write( "x=8 \n" ); document.write( "26x+5z=218 so that 208+5z=218 and z=2 \n" ); document.write( "Going back to the first equation, 8+y+2=11 and y=1 \n" ); document.write( "2(8)+4(1)+5(2)=30 \n" ); document.write( "{8, 1, 2} \n" ); document.write( " |