document.write( "Question 1088968: sqrt(4x-3) = 2+sqrt(2x-5)\r
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document.write( "how to solve equations with two radicals\r
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Algebra.Com's Answer #703306 by natolino_2017(77)![]() ![]() ![]() You can put this solution on YOUR website! First of all, we need to set the restriction to allow the expression to be well defined.\r \n" ); document.write( "\n" ); document.write( "4x - 3 >=0 and 2x - 5 >=0\r \n" ); document.write( "\n" ); document.write( " x >= 3/4 and x>=5/2\r \n" ); document.write( "\n" ); document.write( "Restriction: x>=5/2\r \n" ); document.write( "\n" ); document.write( "now we solve by squaring both sides:\r \n" ); document.write( "\n" ); document.write( "4x-3 = 4 +4sqrt(2x - 5) + (2x-5) \r \n" ); document.write( "\n" ); document.write( "2x-2 = 4sqrt(2x-5) = 2(x-1)\r \n" ); document.write( "\n" ); document.write( "(x-1) is positive according to the restriction, so we can squaring both sides\r \n" ); document.write( "\n" ); document.write( "4(x^2-2x+1) = 16(2x-5)\r \n" ); document.write( "\n" ); document.write( "x^2-2x+1 = 8x-20\r \n" ); document.write( "\n" ); document.write( "x^2-10x+21 = 0\r \n" ); document.write( "\n" ); document.write( "(x-3)(x-7) = 0\r \n" ); document.write( "\n" ); document.write( "so acoording to the last expression we have 2 solution x={3,7}\r \n" ); document.write( "\n" ); document.write( "but according to the restriction x>=5/2 so we don't have to discard any solution.\r \n" ); document.write( "\n" ); document.write( "Final Solution={3,7}\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "@natolino_ \n" ); document.write( " \n" ); document.write( " |