document.write( "Question 1088912: the sum of three numbers is 10. The sum of twice the first​ number, 5 times the second​ number, and 6 times the third number is 47. The difference between 7 times the first number and the second number is 20. Find the three numbers. \n" ); document.write( "
Algebra.Com's Answer #703267 by Fombitz(32388)\"\" \"About 
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1.\"A%2BB%2BC=10\"
\n" ); document.write( "2.\"2A%2B5B%2B6C=47\"
\n" ); document.write( "3.\"7A-B=20\"
\n" ); document.write( "From eq. 3,
\n" ); document.write( "\"B=7A-20\"
\n" ); document.write( "Substitute into eq. 1 and eq. 2,
\n" ); document.write( "\"A%2B%287A-20%29%2BC=10\"
\n" ); document.write( "4.\"8A%2BC=30\"
\n" ); document.write( ".
\n" ); document.write( ".
\n" ); document.write( "\"2A%2B5%287A-20%29%2B6C=47\"
\n" ); document.write( "\"2A%2B35A-100%2B6C=47\"
\n" ); document.write( "5.\"37A%2B6C=147\"
\n" ); document.write( "Multiply eq. 4 by 6 and subtract from eq. 5,
\n" ); document.write( "\"37A%2B6C-48A-6C=147-180\"
\n" ); document.write( "\"-11A=-33\"
\n" ); document.write( "Solve for \"A\", then work backwards to solve for \"B\" and \"C\".
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