document.write( "Question 1088892: Given the circle x^2+y^2-4x+y=7
\n" ); document.write( "1 determine the equation of the tangent to the circle at the point where x=-1
\n" ); document.write( "2 determine the point of intersection of these two tangents
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Algebra.Com's Answer #703254 by josgarithmetic(39617)\"\" \"About 
You can put this solution on YOUR website!
\"y%5E2%2By=-x%5E2%2B4x%2B7\"\r
\n" ); document.write( "\n" ); document.write( "\"y%5E2%2By-4x-%2Bx%5E2-7=0\"\r
\n" ); document.write( "\n" ); document.write( "\"y%5E2%2By%2B4%2B1-7=0\"\r
\n" ); document.write( "\n" ); document.write( "\"y%5E2%2By-2=0\"\r
\n" ); document.write( "\n" ); document.write( "\"y=%28-1%2B-+sqrt%281%2B4%2A2%29%29%2F2\"\r
\n" ); document.write( "\n" ); document.write( "\"y=%28-1%2B-+3%29%2F2\"\r
\n" ); document.write( "\n" ); document.write( "\"system%28y=-2%2Cor%2Cy=1%29\"
\n" ); document.write( "The two lines are tangent at (-1,-2) and (-1,1).\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2-4x%2By%5E2%2By=7\"
\n" ); document.write( "\"x%5E2-4x%2B4%2By%5E2%2By%2B%281%2F2%29%5E2=7%2B4%2B1%2F4\"
\n" ); document.write( "\"%28x-2%29%5E2%2B%28y%2B1%2F2%29%5E2=11%261%2F4\"
\n" ); document.write( "Center of the circle, (2, -1/2).\r
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\n" ); document.write( "\n" ); document.write( "One line will have slope, the negative reciprocal of points (2, -1/2) and (-1,-2) and will contain (-1,-2); and the other line will have slope, the negative reciprocal of points (2, -1/2) and (-1,1) and will contain point (-1,1).
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\n" ); document.write( "Find equation of each of these lines, and find their intersection.
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